A ball is thrown vertically upward with velocity of 10 m/s. Calculate the height attained by the ball and the time taken by it to reach the highest point if the acceleration of the ball is -10 m/s2 during itsmotion.
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A ball is thrown vertically upward with velocity of 10 m/s. Calculate the height attained by the ball and the time taken by it to reach the highest point if the acceleration of the ball is -10 m/s2 during itsmotion.
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Answer:
Let the maximum height attained by the particle be H.
Time taken by it to reach maximum height T=
g
eff
2H
During upward motion :
The particle experiences acceleration due to gravity 10 m/s
2
in downward direction and also, resistive retardation 2 m/s
2
in downward direction.
So, effective acceleration g
eff
=10+2=12 m/s
2
Thus, time of ascent t
a
=
12
2H
During downward motion :
The particle experiences acceleration due to gravity 10 m/s
2
in downward direction and also, resistive retardation 2 m/s
2
in upward direction.
So, effective acceleration g
eff
=10−2=8 m/s
2
Thus, time of descent t
d
=
8
2H
Thus
t
d
t
a
=
3
2