A ball is thrown vertically upward with velocity of 10 m/s. Calculate the height attained by the ball and the time taken by it to reach the highest point if the acceleration of the ball is -10 m/s2 during itsmotion.
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A ball is thrown vertically upward with velocity of 10 m/s. Calculate the height attained by the ball and the time taken by it to reach the highest point if the acceleration of the ball is -10 m/s2 during itsmotion.
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Answer:
[tex]v = u + at \\ at \: highest \: point \: v = 0 \\ 0 = 10 + ( - 10)t \\ - 10 = - 10t \\ t = 1sec \\ v {}^{2} - u { }^{2} = 2as \\ as \: v \: = 0 \\ - 10 {}^{2} = 2( - 10) \times s \\ - 100 = - 20s \\ s = 5m[/tex]
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Answer:
Initial velocity (u) = 10m/s
Final Velocity (v) = 0m/s
Acceleration (a) = -10m/s
a) Let Height = h
Using,
v^2-u^2 = 2ah
0^2 - 10^2 = 2*-10*h
-100/-20 = h
h = 5m
b) Let time taken = t
Using v = u+at
0 = 10+(-10)*t
t =-10/(-10)
t = 1
Therefore, Maximum height achieved = h = 5m
, Time taken to achieve max height = t = 1 sec