A projectile has initially the same horizontal velocity as it would acquire if it had moved from rest with uniform acceleration 3 m/ s^2. for 0.5 mins .If the maximum height reached by it is 80 m then the angle of projection is
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A projectile has initially the same horizontal velocity as it would acquire if it had moved from rest with uniform acceleration 3 m/ s^2. for 0.5 mins .If the maximum height reached by it is 80 m then the angle of projection is
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Answer:
A projectile has initially the same horizontal velocity as it would acquire if it had moved from rest with uniform acceleration of 3ms-2 for 0.5min. If the maximum height reached by it is 80m, then the angle of projection is (g=10ms-2). usinθucosθ=4090 or tanθ=49 or θ=tan-1(49).
Explanation:
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