An electron moving with a velocity of
5
×
10
3
m
/
s
enters into a uniform electric field and acquires a uniform acceleration of
10
3
m
/
s
2
in the direction of initial velocity.
i. Find out the time in which electron velocity will be doubled.?
ii. How much distance electron would cover in this time.?
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Answer:Initial velocity of the electron is u =5×10
4
m/s
Acceleration of the electron is a=10
4
m/s
2
From first equation of motion,
v=u+at
2u=u+at
t=u/a=(5×10
4
)/(10
4
)=5s
(C) 5
Explanation: