The brakes applied to a car produce an acceleration of 6 m/s^2 in the opposite direction to the motion. If the car takes 3s to come to rest after the application of brakes, calculate (i) initial velocity of the car before applying brakes and (ii) the distance covered by the car before stopping.
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Answer:
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Explanation:
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Verified answer
Acceleration
Distance
Final Velocity
v = u + a*t
Initial Velocity u
m/s
Final Velocity v
m/s
Time t
s
Acceleration a
m/s²
RESET VALUES
ANSWER
Given:
Accerleration: a=−6 m/s
2
Time t=2 s
Final velocity, v=0 m/s
v=u+at
0=u−6×2
u=12 m/s
s=ut+
2
1
at
2
s=12×2+
2
1
×(−6)×4
⇒s=12 m