an trunk (iron box) of mass 10^4 g is at rest . an external force is given by an body of mass 100 g at a acceleration of 1m/s^2 . the body is displaced by 100 m
find the work done by the body.(ignore the force of friction)
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an trunk (iron box) of mass 10^4 g is at rest . an external force is given by an body of mass 100 g at a acceleration of 1m/s^2 . the body is displaced by 100 m
find the work done by the body.(ignore the force of friction)
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Verified answer
To find :
work done by the body .
Given :
Formula to be applied :
Solution :
Mass of Trunk = 10^4 g
[tex] \longrightarrow \bold{mass = {10}^{4} g} \\\longrightarrow \boxed{ \bold{ \red{mass = 10000g}}} \\ \longrightarrow \bold{mass = 10 \: kg}[/tex]
Force = mass × acceleration
[tex]\longrightarrow \bold{force = 10\times 1} \\ \longrightarrow \boxed{ \bold{ \green{force = 10 \:N }}}[/tex]
Displacement = 100 m
hence, work done = force × displacement
[tex]\longrightarrow \bold{work = 10n\times 100m} \\ \longrightarrow \boxed{ \bold{ \blue{work \: done= 1000 \: j}}}[/tex]
hence, The work done = 1000 J