A constant torque of 31.4 Nm is exerted on a pivoted wheel. If the angular acceleration of the wheel is
4πππ rad/s2
, then the moment of inertia, will be :
a) 4.8 kg - m
2
b) 6.2 kg - m
2
c) 5.6 kg - m
2
d) 2.5 kg - m
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A constant torque of 31.4 Nm is exerted on a pivoted wheel. If the angular acceleration of the wheel is
4πππ rad/s2
, then the moment of inertia, will be :
a) 4.8 kg - m
2
b) 6.2 kg - m
2
c) 5.6 kg - m
2
d) 2.5 kg - m
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Torque, Moment of Inertia and Angular Acceleration
Torque is the rotational equivalent of Force. Similarly, Moment of Inertia is the rotational equivalent of Mass and Angular Acceleration is the rotational equivalent of Linear Acceleration.
Just like F = ma, in Rotational Mechanics we have:
Where:
= Torque
= Moment of Inertia
= Angular Acceleration
Here, we have our data:
We need the Moment of Inertia (I).
We see that if we take then
We can now easily get the answer:
Thus, The Moment of Inertia is (d) 2.5