A ball is thrown vertically upward with an initial velocity of 80 m/s. Find the height of the ball at time = 10s. (take g=10m/s^2)
(a)300m
(b)800m
(c)10000m
(d)500m
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A ball is thrown vertically upward with an initial velocity of 80 m/s. Find the height of the ball at time = 10s. (take g=10m/s^2)
(a)300m
(b)800m
(c)10000m
(d)500m
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Answer:
According to my opinion, answer should be 1300 m. Hope it helps you. The given Option (1) may have typing error, it should be 1300 m instead of 300 m.
Explanation:
h = ut + 1/2gt^(2)
h = (80)(10) + 1/2(10)(10)^(2)
h = 800 + 500
h = 1300 m ---> Answer
HEIGHT MEANS S
SO LET'S APPLY 2ND EQUATION OF MOTION
G=10
[tex]s=ut+\frac{1}{2} at^2[/tex]
[tex]s=80*10+\frac{1}{2} 10*10^2\\s=800+500\\s=1300-metres[/tex]
since option is not matching ,but i think the answer is 1300 metres
u can also see answer on go.ogle