Two bodies start with the same velocity but one move with acceleration 2m/s^2 and the other with 3m/s^2.After 10 sec,the second body is ahead of the first body by ____m.
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Two bodies start with the same velocity but one move with acceleration 2m/s^2 and the other with 3m/s^2.After 10 sec,the second body is ahead of the first body by ____m.
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◙ Given ◙
Two bodies start with the same velocity.
◙ To Find ◙
After time, t = 10 s, by how much distance will the second body be far from the first body.
◙ We Must Know ◙
Where,
◙ Solution ◙
◘ For body A :-
u = 0 m/s
a = 2 m/s²
t = 10 s
Putting the values :-
◘ For body B :-
U = 0 m/s
A = 3 m/s²
T = 10 s
Putting the values :-
Distance between body A and body B = S - s
= 150 - 100
= 50 m
Hence, body B is 50 m ahead of body A.
Given:
To Find :
By how much distance ,second body ahead of the first body ,after 10 sec
Solution :
Suppose both bodies Start with intital velocity v .
For body 1 :
Acceleration = 2m/s²
Initial Velocity=V
t= 10sec
By third equation of motion :
put t = 10 sec
For body 2:
Acceleration = 3m/s²
Initial Velocity=V
t= 10sec
By third equation of motion :
Put t = 10sec
Therefore,
The second body is ahead of the first body after 10 sec
Kinematic equations for uniformly accelerated motion .
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