[tex] \huge \mathfrak \red{question}[/tex]
A man weighing 80 kg is standing in a trolley weighing 320 kg. The normal contact force between man and trolley is equal to 10n newtons. Find the value of n. (g = 10 m/s2)
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Answer:
A man weighing 80 kg is standing on a trolley weighing 320 kg. The trolley is resting on frictionless horizontal rails. If the man starts walking on the trolley along the rails at speed 1 m/s. Then after 4 s, his displacement relative to ground will be :
Step-by-step explanation:
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Answer:
S.No. Proportion Product of extremes product of means
(i) 1:2::4:8 1×8=8 2×4=8
(ii) 5:6::75:90 5×90=450 6×75=450
(iii) 3:4::24:32 3×32=96
4×24=96
(iv) 2:5::x:15 2×15=30 5x=30 or x=5
(v) 3:6::12:x 3×x or 3x=72⇒x=
3
72
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