five force f1 ,f2,f3,f4,f5 are acting on a particle of mass 2.0kg so that it is moving with 4 m/s2in east direction if f1 is removed then accerlaration becomes 7 m/s2in north then acceleration of the block if only f1
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five force f1 ,f2,f3,f4,f5 are acting on a particle of mass 2.0kg so that it is moving with 4 m/s2in east direction if f1 is removed then accerlaration becomes 7 m/s2in north then acceleration of the block if only f1
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Given that when all forces are acting on the particle then its acceleration is 4 m/s^2 towards East
So now we can write
so above is the acceleration of the mass when only F1 force is acting on it
Answer:
acceleration=
Explanation:
vector(F1+F2+F3+F4+F5) =2*(4i)=8i
Vector(F2+F3+F4+F5) =2*(7j)=14j
vector(F1) + 14j=8i
magnitude(F1)= =
a=F1/m=