a stone is thrown vertically uowards.it decelerates at a rate of 9.8m/s^2.it reaches a greatest height of 16.53 m.calculate its initial speec
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a stone is thrown vertically uowards.it decelerates at a rate of 9.8m/s^2.it reaches a greatest height of 16.53 m.calculate its initial speec
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Answer: Given :
a = (-9.8) m/sec^2
s = 16.53m
v = 0m/sec
u = ?
Explanation: By formula
v^2 = u^2 +2as
0 = u^2 + (-323.988)
u = 17.99 m/sec