an object starts from rest and attains an uniform acceleration of 4m/s2.It's velocity at the end of half meter is?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
Given Data:Initial velocity = Vi = 0 m/s ( Because object starts its motion from rest)
Acceleration = 4 m/s²
Distance = 0.5 m
Final velocity = Vf = ?
Solution:
Using 3rd Equation of Motion,
2aS = Vf² - Vi²
Vf² = 2aS + Vi²
Vf² = 2 (4) (0.5) + (0)²
Vf² = 4
Vf = √ 4
Vf = 2 m/s²
Hence, the velocity at t he end of half meter is 2 m/s²
Hope it will help you.
Thanks.
Initial velocity= 0m/s
Acceleration = 4m/s2
Final velocity =?
Distance = s=0.5 m
From third equation of motion
V^2 - u^2=2as
V2= 2x0.5x4
=2×5×4/10
=4m/s
V=2m/s
Therefore final velocity= 2m/s