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Explanation:
[tex]\mathsf{x- \frac{2x+8}{3}=\frac{1}{4}(x- \frac{2-x}{6})-3}[/tex]
[tex]\mathsf{==>4(x- \frac{2x+8}{3})=x-\frac{2-x}{6}-3}[/tex]
[tex]\mathsf{==>4x-\frac{8x+32}{3}=x - \frac{2-x}{6}-3}[/tex]
[tex]\mathsf{==>\frac{12x-8x-32}{3}=\frac{6x-2+x-18}{6}}[/tex]
[tex]\mathsf{==>\frac{4x-32}{3}=\frac{7x-20}{6}}[/tex]
[tex]\mathsf{==>6(4x-32)=3(7x-20)}[/tex]
[tex]\mathsf{==>24x-192=21x-60}[/tex]
[tex]\mathsf{==>24x-21x=-60+192}[/tex]
[tex]\mathsf{==>3x=132}[/tex]
∴ [tex]\mathsf{x=\frac{132}{3}=44}[/tex]
Answer: x = 44
I hope this helps. :D
Answer:
hope it will help you dear