.A bullet of mass 4g when fired with a velocity of 50m/s,can enter a wall up to a depth of 10cm.How much will be the average resistance offered by the wall?
Share
.A bullet of mass 4g when fired with a velocity of 50m/s,can enter a wall up to a depth of 10cm.How much will be the average resistance offered by the wall?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
hope it helps....
Given:
Mass of the Bullet = 0.004 kg
Initial Velocity = u = 50 m/s
Depth = s = 10cm = 0.1 m
To find:
Average resistance offered by the wall
Solution:
Final velocity = 0
According to the equation of velocity
v² - u² = 2as
a = (0 - 2500) / 2 x 0.1
a = - 2500/ 0.2
= - 1250
Now,
F = ma
F = 0.004 x -1250
= - 50N
Answer: Force Exerted by wall on Bullet is +50N ( Newton's third law)