Rain appears to fall vertically downward to a man moving with a
velocity of 4 m/sec. when he doubles his speed then the rain appears to
strike him at an angle of 45' from horizontal. Then what is the actual
velocity of rain drops?
Share
Rain appears to fall vertically downward to a man moving with a
velocity of 4 m/sec. when he doubles his speed then the rain appears to
strike him at an angle of 45' from horizontal. Then what is the actual
velocity of rain drops?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Explanation:
Initial velocity of the man, me = 4 m/s
Final velocity of the man, m'e = 8 m/s
m'm = m'e - me = 8 - 4 = 4 m/s
tan 45 = rm/m'm
rm = (m'm) tan 45 = 1
re = √(rm)^2 + (me)^2 = 4 √2 m/s
θ = tan^-1 (me / rm) = tan^-1 (1)
θ = 45° degree
Hence the speed of the raindrop is 4 √2 m/s and the angle is 45°.
Also, learn more
Rain is falling vertically downwards with a velocity of 3 km/hr. a man walks in the rain with a velocity of 4 km/hr. the raindrops will fall on the man with a velocity of?
brainly.in/question/4750322