A bus startng from rest Moves with a uniform acceleration of 0.1 meter/second for 2 minutes
Second
find
speed acquired
The distance travelled in the given period of time
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A bus startng from rest Moves with a uniform acceleration of 0.1 meter/second for 2 minutes
Second
find
speed acquired
The distance travelled in the given period of time
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Answer:
We are given with certain Kinematics quantities of a bus.
Finding speed acquired:
Given:
Uniform accleration of the bus (a) = 0.1 m/s²
Time travelled by the bus (t) = 2 mins
Started from rest. (u = 0 m/s)
❒ Time taken = 2 mins = 2 × 60 = 120 s
By using 1st equation of motion,
\large{ \because{ \underline{ \boxed{ \rm{v = u + at}}}}}∵v=u+at
Plugging the given values to find the speed acquired:
➝ v = u + at
➝ v = 0 + (0.1)120
➝ v = 120 / 10 m/s
➝ v = 12 m/s
Finding distance travelled:
Now as we have got our final velocity, Initial velocity and accleration is given. So, By using 3rd equation of motion,
\large{ \because{ \underline{ \boxed{ \rm{ {v}^{2} - {u}^{2} = 2as}}}}}∵v2−u2=2as
Plugging the given values to find distance (s):
➝ v² - u² = 2as
➝ 12² - 0² = 2(0.1)s
➝ 144 = 0.2s
➝ s = 144 / 0.2 m
➝ s = 720 m
Hence, the required values of speed acquired and Distance travelled by the bus:
\large{ \therefore{ \underline{ \boxed{ \bf{ \green{12 \: m {s}^{ - 1} and \: 720 \: m}}}}}}∴12ms−1and720m