See who will solve this easy problem. The person who gives the perfect answer he will be BRAINLIEST.
PLS ITS URGENT.
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See who will solve this easy problem. The person who gives the perfect answer he will be BRAINLIEST.
PLS ITS URGENT.
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Given we square side=14/3 m
hence perimeter of quare(p1)=4*side
= 4*(14/3)
=56/3m
=18.667 m
Also given rectangle length (l)=26/5 m
breadth(b)= 17/3 m
hence perimeter of rectangle (p2)=2*(l+b)
=2*[(26/5) + (17/3)]
=2*10.86667
= 21.73334 meter
Hence p2>p1
hence perimeter of rectangle is greater
Answer:
Hey friend hope this will help you.............
Given we square side=14/3 m
hence perimeter of quare(p1)=4*side
= 4*(14/3)
=56/3m
=18.667 m
Also given rectangle length (l)=26/5 m
breadth(b)= 17/3 m
hence perimeter of rectangle (p2)=2*(l+b)
=2*[(26/5) + (17/3)]
=2*10.86667
= 21.73334 meter
Hence p2>p1
hence perimeter of rectangle is greater