*Seg PM is a median of △PQR. If PQ = 40, PR = 42 and QR = 58 then find length of PM.*
1️⃣ 25
2️⃣ 20
3️⃣ 21
4️⃣ 29
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*Seg PM is a median of △PQR. If PQ = 40, PR = 42 and QR = 58 then find length of PM.*
1️⃣ 25
2️⃣ 20
3️⃣ 21
4️⃣ 29
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In PQR, point m is the midpoints of side QR.
QM=MR= ½QR
PQ² + PR² = 2PM² + 2 QM² {by A]
( 40 )² + ( 42 )² = 2( 29 )² + 2QM²
1600 + 1764 = 1682 + 2QM²
3364 - 1682 = 2QM²
QM² = 841
QM = 29
QR = 2×29
QR = 58
HENCE, QR = 58
In △PQR;
PQ=8,QR=5,PR=3
(8)2=8, (5)2=5, (3)2=3 and 3+5=8
Thus, the longest length of the sides of the triangle is PQ=8, opposite to ∠R
The square of the largest numbers is equal to the sum of the square of the other two numbers.
∴△PQR form a right-angled triangle, where angle R is of 90∘
Answer:
Step-by-step explanation:
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