Particle 'A' has a velocity of VA=8m/s
along positive Xaxis.Particle B has a
velocity VB= ( 4i+4Underoot3j ;) m/s
Find the magnitude of the relative velocity of B with respect to A
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Particle 'A' has a velocity of VA=8m/s
along positive Xaxis.Particle B has a
velocity VB= ( 4i+4Underoot3j ;) m/s
Find the magnitude of the relative velocity of B with respect to A
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Answer:
8 m/s
Explanation:
Relative velocity of B wrt A VBA = VB–VA
velocity of A = 8i^
VBA = 4i^ + 4 unroot 3j^ – 8i^
= –4i^ + 4 unroot 3 j^
magnitude = unroot( 4²+ (4 unroot 3)²)
= 8 m/s