Shashikant has in the shape of rhombus. The length of each side of garden is 35m and its diagonal is 42m long. After growing the vegetable in it. He want to divide it is seven equal parts and look after each part. Onces upon a week - Find the area of garden which he to look after each part.
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Answer:
Let ABCD be the garden
Side, DC = 35 m
Diagonal, DB = 42 m
We know that the diagonals of a rhombus bisect each other at right angles.
Therefore,
DE = 1/2×42 = 21 m
In right-angled triangle DEC, applying pythagoras,
CD² = CE² + DE²
CE² = CD² - DE² = 35² - 21²
CE² = 784
CE = 28 m
Now,
Area of △DBC = 1/2×DB×CE
= 1/2×42×28
= 588 m²
Therefore,
Area of the garden ABCD = 2×588
= 1176 m²
Answer:
105m^2
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Step-by-step explanation:
area of rhombus = pq/2
area of rhombus = (42 * 35)/2
= area of rhombus = 735
for 7 equal parts area 735/7
= 105m^2