short note on BIRENDER SINGH DHANOA
Share
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
First we have to substitute values :-
4a+3b/3b = \sf{ (4×2)+\dfrac{3×3}{3×3}}(4×2)+
3×3
3×3
=> \sf{ (4×2)+\dfrac{(3×3)}{(3×3)}}(4×2)+
(3×3)
(3×3)
=> \sf{ 8+\dfrac{9}{9}}8+
9
9
HERE BOTH 9 ARE IN DIVISION FORM SO THEY WILL BE CANCELLED.
=> \sf{ \dfrac{9}{9} = \dfrac{1}{1}}
9
9
=
1
1
=> \sf{ 8+ \dfrac{1}{1}}8+
1
1
=>8+1
=>9
Verified answer
[tex] \\ { \huge{ \large{ \underline{ \pmb{ \pmb{ \pmb{ \pmb{ \pmb{ \sf{ \color{red}{Answer}}}}}}}}}}} \\ \\ [/tex]
[tex]\hookrightarrow[/tex] Now Learn About him in Brief :
[tex] \\ \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \\ \\ [/tex]
[tex]{ \qquad{ \rule{200pt}{2pt}}}[/tex]