show that the point A(8,3),B(0,9) and C(14,11) are the vertices of an isosceles right angled triangle
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show that the point A(8,3),B(0,9) and C(14,11) are the vertices of an isosceles right angled triangle
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AB=√(0-8)^2 +(9-3)^2 ,
=√(-8)^2 +(6)^2
=√64+36
=√100
AB=10.
BC=√(14-0)^2 +(11-9)^2
=√(14)^2 + (2)^2
=√196+4
=√200
CA=√(8-14)^2 + (3-11)^2
= √(-6)^2 + (-8)^2
=√36+64
=√100
=10
two sides of a triangle are equally so they are the vertices of an isosceles triangle.
comment me was this answer help u in solving ur problem.
Answer:
Yeah Both are equal
Step-by-step explanation:
(8,3) (0,9)
10
you should do this and you will get the other 3 sides as, , , 10 and since two sides are equal it is an isoceles triangle