Show that:
(1) tan 48° tan 23° tan 42° tan 67° = 1
(i) cos 38° cos 52° – sin 38° sin 52° = 0
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Show that:
(1) tan 48° tan 23° tan 42° tan 67° = 1
(i) cos 38° cos 52° – sin 38° sin 52° = 0
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Answer:
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Answer:
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Step-by-step explanation:
tan48° tan42° tan23° tan67°
= tan48° tan(90°- 48°) tan23° tan(90°- 67°)
=tan48° cot 48° tan23° cot23°
=tan48°.1/tan48° tan23°. 1/tan23°
= 1
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