Show your own working for this question and i am warning: Only CuriousRose will answer no one will give answer
The perimeter of a triangle is 35 cm. The length of the third side is twice the
length of the first side. The length of the second side is half the length of the
first side. Find the lengths of the three sides.
Share
Here is your answer. mark me as the brainliest.
Verified answer
Given :
Perimeter of triangle = 35 cm
To find :
The length of the three sides of triangle
Solution :
Let the unknown first side be x
As it given that length of second side is half the length of first side i.e. "half of x" :-
=> Second side length = x/2
----------------------------------------------------------
It is also given that length of the third side is twice the length of the first side i.e "2 times x" :-
=> Third side length = 2x
----------------------------------------------------------
Hence we have the representatives of each side of triangle which is x, x/2 and 2x which add up to give the perimeter 35. Let's make an algebraic equation to get an answer for it...
[tex] = > x + \frac{x}{2} + 2x = 35 \\ [/tex]
[tex] = > \frac{x}{1} + \frac{x}{2} + \frac{2x}{1} = 35 \\ [/tex]
[tex] = > \: \frac{x + 2x + 4x}{2} = 35 \\ [/tex]
[tex] = > \frac{7x}{2} = 35 \\ [/tex]
[tex] = > \: 7x = 35 \times 2[/tex]
[tex] = > \: 7x = 70[/tex]
[tex] = > x = \frac{70}{7} = 10 \\ [/tex]
----------------------------------------------------------
Now we'll substitute the value of x to get the length of all the three sides of triangle:--
First side = x = 10 cm
Second side = x/2 = 10/2 = 5cm
Third side = 2x = 2 × 10 = 20cm
----------------------------------------------------------
Therefore, the length of the three sides of the triangle are 10cm, 5cm and 20 cm respectively.