sides AB and AC of a triangle ABC are extended to point P abd Q respectively .also ANGLE PBC<ANGLE QCB show that AC>AB
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sides AB and AC of a triangle ABC are extended to point P abd Q respectively .also ANGLE PBC<ANGLE QCB show that AC>AB
only brainliest can answer this
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angle ACB equal to 180 -angle QCB(LP)
but angle PBC<angle QCB
so angle ACB< angle ABC
AB<AC
we know that angle of opposite sides is Greater then it's opposite side must be greater
hope it helps you
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