sides of a triangle are in the ratio of 17:25:12and it's perimeter is 405 cm .find it ? please help me.
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sides of a triangle are in the ratio of 17:25:12and it's perimeter is 405 cm .find it ? please help me.
sides of a triangle are in the ratio of 17:25:12and it's perimeter is 405 cm .find it ? please help me.
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Let the sides of triangle are 17x , 25x & 12x.
Perimeter = 405 cm
As we know, P of ∆ = a + b + c
⟹ 17x + 25x + 12x = 54x
[tex] \mathcal{ \underline \blue{According \: to \: Question -}}[/tex]
Perimeter of Triangle ∆ = 405 cm
⟹ 17x + 25x + 12x = 405 cm
⟹ 54x = 405 cm
⟹ x = [tex] \frac{\cancel{405}^{\cancel{ \: \:45}^{\: \: 15}}}{\cancel{54}^{\: \: \cancel{6}^{\:\: 2}}}[/tex]
[tex]\blue \therefore[/tex] x = [tex] \frac{15}{2}[/tex]
Now,
17x = 17 × [tex] \frac{15}{2}[/tex] = 127.5 cm
25x = 25 × [tex] \frac{15}{2}[/tex] = 187.5 cm
12x = [tex]\cancel{12}^{6} \times \frac{15}{\cancel2}[/tex] = 90 cm
[tex] \large\underline\red{Answer} [/tex]
Hence the three sides are ; 127.5 cm , 187.5 cm & 90 cm
If you want to check :-
Add the three sides = 90 + 127.5 + 187.5 (cm)
= 405 cm
Hope this helps you :)
Answer:
I am Ganga from Belagavi