simplify (b²+c²)-[b²-b(b+c)+c²]
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Answer:
chk thiss
Step-by-step explanation:
(b2+c2)-[b2-b(b+c)+c2]
=(b2+c2)-[b2-b2-bc+c2]
=b2+c2-b2+b2+bc-c2
=b2+bc
Verified answer
Answer:
[tex]{b}^{2} + bc[/tex]
Step-by-step explanation:
[tex] = ( {b}^{2} + {c}^{2} ) - ( {b}^{2} - {b}^{2} - bc + {c}^{2} ) \\ = ( {b}^{2} + {c}^{2} ) - ( - bc + {c}^{2} ) \\ = {b}^{2} + {c}^{2} + bc - {c}^{2} \\ = {b}^{2} + bc[/tex]