Sin square theta +cos square theta
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Answer:
1
Step-by-step explanation:
Put sin \theta = \frac{P}{H}, cos \theta = \frac{B}{H},
Sin^2 \theta + Cos^2 \theta= 1
(\frac{P}{H})^2 + (\frac{B}{H})^2 = 1
\frac{(P^2 + B^2)}{H^2} = 1
Ina triangle, by pythogoras,
P^2 + B^2 = H^2
Hence, \frac{H^2}{H^2} = 1.