sinA/1+cosA + 1+cosA/sinA
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Question
sinA/1+cosA + 1+cosA/sinA
Solution
SinA/(1 + CosA) + (1 + CosA)/SinA
= [(SinA)^2 + (1+CosA)^2]/[SinA(1 + CosA)]
= [(SinA)^2 + (CosA)^2 + 1 + 2CosA]/[SinA(1 + CosA)]
= [2(1 + CosA)]/[SinA(1 + CosA)]
( since, (SinA)^2 + (CosA)^2 = 1 )
= 2/SinA = 2CosecA
Hence LHS=RHS.
Answer:
see the attachment
Step-by-step explanation:
hope it helps you