the brother/sister watching it please help me it's urgent
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the brother/sister watching it please help me it's urgent
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Answer:
1. The impulse imparted to the mass is 0.5 kg-m/s.
It is given that,
Mass of the object, m = 3 kg
Force acting on the object, F = 5 N
Time of contact, t = 0.1 s
Let J is the impulse imparted to mass. It is equal to the product of force and time of contact. It is given by :
J=F×t
J=5 N×0.1 s
J = 0.5 kg-m/s
So, the impulse imparted to the mass is 0.5 kg-m/s. Hence, this is the required solution.
2. From Newton's second law of motion, the applied force is directly proportional to the acceleration produced or F=ma
The unit of force is newton in SI denoted by the symbol N.
Forces acting on a mass m 1 with acceleration a 1 and mass m 2 with acceleration a 2 are as given below.
m 1 = F/a 1 = 5/8 kg
m 2 = F / a 2 = 5/24 kg
M=( 5/8 +5/24 ) kg = ( 5/6 )kg
Acceleration produced in M (when the two masses are tied together),
a= F /M =5/5/6 =6 ms^-2.
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