Slove the equation step by step (36X⁴)÷(6X²)
Share
Slove the equation step by step (36X⁴)÷(6X²)
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Step-by-step explanation:
Step-by-step explanation:6x^2-5√3x+3 =0
Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0
Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms
Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0
Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0taking 3x and √3 from 1st and 2nd bracket
Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0taking 3x and √3 from 1st and 2nd bracket 3x(2x-√3) - √3(2x-3)
Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0taking 3x and √3 from 1st and 2nd bracket 3x(2x-√3) - √3(2x-3) taking 2x -√3 common
Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0taking 3x and √3 from 1st and 2nd bracket 3x(2x-√3) - √3(2x-3) taking 2x -√3 common (2x-√3) (3x-√3)
Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0taking 3x and √3 from 1st and 2nd bracket 3x(2x-√3) - √3(2x-3) taking 2x -√3 common (2x-√3) (3x-√3)therefore the roots of the given quadratic equation are
Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0taking 3x and √3 from 1st and 2nd bracket 3x(2x-√3) - √3(2x-3) taking 2x -√3 common (2x-√3) (3x-√3)therefore the roots of the given quadratic equation are x= √3/2 and x=√3/3
Explanation:
Answer:
give me thanks I'll definitely give u more thanks