3) if the ratio of the sum of the first n terms of two APs(7n–1) : (4n+27) then find the ratio of the their 9th term
sn= 7n+1/ sn1= 4n+27
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3) if the ratio of the sum of the first n terms of two APs(7n–1) : (4n+27) then find the ratio of the their 9th term
sn= 7n+1/ sn1= 4n+27
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Answer:
ratio of n terms =(7n-1):(4n+27)
1st AP=7n-1
2nd AP =4n+27
1st AP 9th term
7(9)+1=64
2nd AP 9th term
4(9)+27=63
solution,
ratio of two AP's 9 the term=64:63
64:63