Sodium surface is illuminated by ultraviolet and visible radiation successively and the stopping potential determined. This stopping potential is
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Sodium surface is illuminated by ultraviolet and visible radiation successively and the stopping potential determined. This stopping potential is
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Explanation:
ANSWER
λ for U.V is less than λ for visible light
ν for U.V is greather than ν for visible light
∴ potential is greater for U.V light.
as K.Eα
λ
1
Answer:
Explanation:
As per the equation
E = hv - Ф or evo = h∨ - Ф
We know that frequency of uv is greater than visible light
Stopping potential of uv is greater