Solve 2, 4 and 6 question plz...
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Solve 2, 4 and 6 question plz...
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Answer:
2)80° 4) angle MPN=140° 6)110°
Step-by-step explanation:
2)Let 2 angles by 2x
75+125+2x=360(property of quadrilateral)
2x=360-200
x=80°
4) we know that the sum of all angles of a quadrilateral is 360°.
Therefore, angle PNO+ angle PMO+ angle MON +angle MPN=360°( angle PNO and angle PMO is 90 degrees at as it is given that tangents are perpendicular to the radius)
=>90+90+40+angle MPN=360
=>220+angleMPN=360
=>angleMPN=360-220
=>angle MPN=140°
6) let x be the measure of the fourth angle.
we know that the sum of the interior angles of a quadrilateral s360 degrees
since three angles are given it us so we can find the fourth angle
therefore, 55+55+140+x=360°
=>250+x=360
=>x=360-250
=>x=110°
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Q2
let 2 angles be 2x 75+125+2x=360(property of quad.) 2x-360-200
x=160/2
x=80
Q4
all angles of quadrilateral is 360°
<P + <N + <O + <M = 360
<P +90 +90 +40 = 360
<P = 360-220
<P = 140°
Q6
The measurement of the fourth angle is 110 degrees.
Explanation:
Let x be the measure of the fourth angle.
We know that the sum of the interior angles of a is 360 degrees.
We'll use this fact to find the measurement of the fourth angle of the quadrilateral.
We have been given that two angles are 55 degrees each and the third angle is 140 degrees. Hence, we have
[tex] {55}^{o} + {55}^{o} + {140}^{o} + x = {360}^{o} [/tex]
[tex] {110}^{o} + {140}^{o} + x = {360}^{o}[/tex]
[tex] {250}^{o} + x = {360}^{o} [/tex]
[tex]x = {(360 - 250)}^{o} [/tex]
[tex]x = {110}^{o} [/tex]
Therefore, the measurement of the fourth angle is 110 degrees.