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(10.)
We have (3×5×7)+7=105+7=112
=2×2×2×2×7, which has more than two factors
Thus, the given number is a composite number.
☞(11.)
Smallest Composite Number = 4
=2×2
Smallest Prime Number = 2
HCF of (4,2) = 2
☞(12.)
120= 2×2×2×3×5
144 =2×2×2×2×3×3
HCF of (120,144) = 2×2×2×3=24
LCM of (120,144) =2×2×2×2×3×3×5 = 720
☞(13.)
Length = 8m 25cm = 825 cm
Breadth = 6m 75cm = 675 cm
Height = 4m 50 cm = 450 cm
Now we have to find the HCF of these numbers
825=3×5×5×11
675 = 3×3×3×5×5
450 = 2×3×3×5×5
Longest rod = HCF of (825,675 and 450) = 3×5×5 =75
☞(14.)==>
HCF×LCM = Product of two numbers
11×253×R=253×440
R = (253×440)/(11×253)
R=40
☞(16) same as 15
check=>
☞18.