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Answer:
1)The two no.s are 43 and 15
2)The two no.s are 27 and 29
3)The multiples of 7 are 252, 259, 266
4) He traveled 20 km by train
Step-by-step explanation:
Let greater no be x and other no. be y
x+y=58
+ x-y=28
__________
2x = 86
x = 86/2
x = 43
x+y = 58
43+y = 58
y = 58-43
y = 15
2) Let smaller no. be x
So, other no will be x+2
Hence, x+x+2=56
2x = 56-2
x =54/2
x = 27
Hence, the two no.s are 27(x) and 29 (x+2)
3) Let the multiples of 7 be x, x+7, x+14
Hence, x+x+7+x+14=777
3x+21 =777
3x= 777-21
3x=756
x=756/3
x=252
Hence the multiples of 7 are 252(x), 259(x+7), 266(x+14)
4) Let the distance traveled by train be x km
so, distance traveled by bus will be (2x) km
Hence, total distance = 10km + x+2x
70 km = 10 +3x
70-10 =3x
60/3 =x
20 km = x
Hence, he traveled 20 km by train