solve by substiution method x=5 ; 2x+y=10
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[tex]\bf{\underline{\underline{Given\: :}}}[/tex]
[tex]\mathsf{ \bigstar\: 2x + y = 10}[/tex]
[tex]\mathsf{ \bigstar\: x = 5}\\ \\[/tex]
[tex]\bf{\underline{\underline{To\:find\: :}}}[/tex]
[tex]\mathsf{\bigstar\: Value\:of\: y}\\ \\[/tex]
[tex]\bf{\underline{\underline{Solution\: :}}}[/tex]
[tex]\mathtt{\implies\: 2x + y = 10}[/tex]
[tex]\mathtt{\implies\: 2(5) + y = 10\:\:(Using\:x = 5)}[/tex]
[tex]\mathtt{\implies\: 10 + y = 10}[/tex]
[tex]\mathtt{\implies\: y = 10 - 10}[/tex]
[tex]\mathtt{\implies\: y = 0}\\ \\[/tex]
[tex]\mathsf{\diamond\:\: Since, \:y = 0}[/tex]
[tex]\mathsf{\implies\: y\: will\: not\: exist}\\[/tex]
Given equation,
[tex]x=5\\2x+y=10[/tex]
Substituting, x=5, in the 2nd eq, we get,
[tex]2x+y=10\\2(5) + y = 10\\10+y=10\\y=10-10\\\\\boxed{\boxed{\bold{y=0}}}[/tex]