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Step-by-step explanation:
Let 3x+y =u
3x-y =v
1/u +1/v =3/4 (1) by multiplying 2 in equation (1)
1/2u- 1/2v=-1/8 (2)
1/2u + 1/2v =3/8 (1) by adding equation equation (1) and (2)
1/2u+1/2u = 2/8
2/2u = 1/4
1/u =1/4
u=4
by substituting u value in (1)
1/u +1/v =3/8
1/v+1/4 =3/4
1/v= 3/4-1/4=2/4=1/2
v=2 again solving the value of v and u
3x+y=4(3)
3x-y=2(4) by adding (3) and (4)
6x=6
x=1
by substitution x=1 in equation (3)
y=1
Answer
X= 1 and Y =1
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Verified answer
Answer:
[tex]<p style="color:cyan;font-family:cursive;background:black;font size:40px;">
Let 1/3x + y = a , and 1/3x - y = b ,
a + b = 3/4 -----------------> (1)
4a + 4b = 3 -------------> (1)
also ,
a/2 - b/2 = -1/8
(a - b)/2 = -1/8
a - b = -1/4
4a - 4b = -1 ---------------------------> (2)
Adding equations (1) and (2) :-
4a + 4b = 3
4a - 4b = -1
--------------------
8a = 2
a = 2/8
a = 1/4
4a - 4b = -1
4*1/4 - 4b = -1
1 - 4b = -1
4b = 1 + 1
4b = 2
b = 2/4
b = 1/2
1/3x + y = a
1/3x + y = 1/4
3x + y = 4 -----------------> (3)
1/3x - y = b
1/3x - y = 1/2
3x - y = 2 -----------------> (2)
Adding equations (3) and (4) :-
3x + y = 4
3x - y = 2
--------------------------
6x = 6
x = 1
3x + y = 4
3*1 + y = 4
y = 4 - 3 = 1
Hence,
x = 1 , y = 1 </p>[/tex]
[tex]<marquee bgcolor = "white" behaviour-move><font color ="green"><h1>#PHENOMENAL ♡♡♡♡♡</ht></marquee>[/tex]