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Verified answer
Given :-
To Find :-
Formula used :-
Solution :-
Let us Assume That, Length of QC is xcm.
Than,
By Tangent External Points we Have :-
→ AP = AR = 6cm.
→ PB = BQ = 8cm.
→ QC = CR = x cm.
Or, we can say That,
→ AB = 14cm.
→ AC = (6+x)cm.
→ BC = (8+x) cm.
So,
→ Semi-Perimeter of ∆ = (14 + 6 + x + 8 + x) / 2
→ s = (28 + 2x)/2
→ s = (14+x) cm.
Now, Putting both Values in above told formula, we get,
→ s * inradius = Area of ∆
→ (14+x) * 4 = 84
Dividing both sides by 4,
→ (14+x) = 21
→ x = 21 - 14
→ x = 7cm.
Hence ,
→ AC = (6+x) = 6 + 7 = 13cm.
→ BC = (8+x) = 8 + 7 = 15cm.
Hence, Rest two Sides of ∆ABC are 13 & 15 cm.
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