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Answer:
c) 0
Step-by-step explanation:
We know that,
x³-y³=(x-y)(x²+xy+y²) ........(1)
Given that,
x/y+y/x= -1
(x²+y²)/xy= -1
x²+y²= -xy
x²+y²+xy=0
(x²+xy+y²)=0
Multyplying by (x-y) on both sides we get,
(x-y)(x²+xy+y²)=(x-y)×0
From (1), we get,
x³-y³=0
HOPE IT HELPS,
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Answer:
[tex]\huge\underline\bold\red{♡AnsWeR♡}[/tex]
[tex] {x}^{2} {y}^{2} = 0[/tex]