Solve previous year Question of iit jee
Chapter :- sequence and series
Share
Solve previous year Question of iit jee
Chapter :- sequence and series
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Option D)
[tex] log_{e}( \frac{4}{2} ) [/tex]
Refer the attachment
Verified answer
Answer:
Sum of series 1/1*2 - 1/2*3 + 1/3*4 --------- upto is logₑ(4/e)
Step-by-step explanation:
solution :- We have 1/1*2 - 1/2*3 + 1/3*4 -------upto ∞
Now , we can write this like as
Used logarithmic series
log(1+x) = x - x²/2 + x³/3 - x⁴/4
Similarly here x = 1