Solve : tan 5 theta = cot theta. where 0‹theta‹ 90
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Solve : tan 5 theta = cot theta. where 0‹theta‹ 90
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tanθ=cot = tan= 1/ cot
tan2θ=1
tanθ=±1
Value of tanθis positive in first quadrant.
Neglect the negative value as θis acute.
tanθ=1
tanθ=tan45o
⇒θ=45∘
Step-by-step explanation: