solve the 10 and 11 ouestion plz help me
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Here is your Answer!
Q10)
Given that
Complementary angle
(3x+4)° and (x-2)°
We know that
Sum of Complementary angle = 90°
Now
3x+4+x-2 = 90°
4x =90-2
X = 88/4
X = 22
Put the Value X in angle
3×22+4= 66+4
= 70°
22-2 = 20°
_________________________
Q11)
Given that supplementary angle
We know that
The sum of supplementary angle= 180°
Now
2x +10 +3x+5 = 180°
5x +15 = 180°
5x = 165
X = 165/5
X = 33
Put the Value of X in angle
2×33+ 10 = 66+10 = 76°
3×33+5 = 99+5 = 104°
Hope it's helpful ✌✌