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Answer:
proved
Step-by-step explanation:
given : AB = EF, BC = DE, AB⊥BD , FE⊥CE
to prove : ΔABD≅ΔFBC
Proof : as, BC = DE (given)____ (i)
adding CD to both sides of eq. (i)
BC + CD = DE + CD
BD = CE _______________(ii)
now in ΔABD and ΔFEC,
AB = FE (given)
BD = CE (from eq. (i))
∠ABD = ∠FEC (given ⊥)
therefore, ΔABD ≅ ΔFBC
HENCE PROVED