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Answer:
1
Step-by-step explanation:
(x^(ac) *x^(ba) * x^(bc) )/ (x^(bc) * x^ac * x^ab)
=1
Q =( xᵃ/xᵇ)^c * (xᵇ/x^c)ᵃ * (x^c/xᵃ)ᵇ
= x^(a-b)c * x^(b-c)a * x^(c-a)b
= x^(ca-bc) * x^(ab-ac) * x^(bc-ab)
= x^(ac-bc+ab-ac+bc-ab)
= x⁰
= 1
Hope that answered your question.