solve the equation . please yrr
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Answer:
-11
Step-by-step explanation:
x'2-x'2-2x+2x+4=x+3/2
+4(2)=x+3
+8-3=x
x=+5
Mark me BRAINLIEST please
QUESTION :
[tex] \dfrac{ {x}^{2} \: - \: (x + 2)( \times - 2) }{x + 3} = \: \dfrac{1}{2} [/tex]
ANSWER : x = 5
Identity used : (a-b)(a+b) = a² - b²
Solution :
(x+2)(x-2) = x² - (2)² = x² - 4
[tex] \sf \implies \: \dfrac{ {x}^{2} \: - \: (x + 2)( x - 2) }{x + 3} = \dfrac{1}{2} \\ \\ \sf \implies \: \dfrac{ {x}^{2} - \: ( {x}^{2} \: - 4 \: ) }{x + 3} \: = \: \dfrac{1}{2} \\ \\ \implies \sf \dfrac{ {x}^{2} \: - \: {x}^{2} \: + 4}{x + 3} \: = \dfrac{1}{2} \\ \\ \implies \sf \dfrac{4}{x + 3} = \: \dfrac{1}{2} [/tex]
on cross multiplying, we get ;
=> 4×2 = 1×(x+3)
=> 8 = x + 3
=> x = 8 - 3
=> x = 5