solve the following equation.
2X^2 + 3x + 5 = 0
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solve the following equation.
2X^2 + 3x + 5 = 0
Hello Friends How Are You I am back .
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Answer:
=>2x^2-2x+5x+5
=>2x(x-1)-5 (x+1)
=>(x-1)(2x-5)
Hope it helps.
Explanation:
You can see that it is a quadratic equation and use the formula x = {-b +- √(b^2-4ac)}/2a
Here we have a = 2, b = 3 and c = 5
therefore, x = {-3 +- √((-3)^2-4*2*5)}/2*2
= (-3 +- √(9-40))/4
=(-3 +- √(-31))/4
We have i=√(-1)
therefore, x = (-3 + i√31)/4 or (-3 - i√31)/4
Hope it helps.