solve the following equation
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[tex] \frac{3t + 1}{16} - \frac{2t - 3}{7} = \frac{t + 3}{8} + \frac{3t - 1}{14} \\ \\ \frac{21t + 7 - 32t - 48}{112} = \frac{7t + 21 + 12t - 4}{56} \\ \\ \frac{ - 11t - 41}{112} = \frac{19t + 17}{56} \\ \\ 56( - 11t - 41) = 112(19t + 17) \\ \\ - 616t - 2296 = 2228t + 1904 \\ \\ - 616t - 2228t = 1904 + 2296 \\ \\ - 2844t = 4200 \\ \\ t = \frac{ - 4200}{2844} \\ \\ t = \frac{ - 350}{237} [/tex]
Answer:
Step-by-step explanation:
3t+1-2t-3=t+3+3t-1
16 7 8 14
find there LCM=112
112(3t+1)-112(2t-3)=112(t+3)+112(3t-1)
16 7 8 14
7(3t+1)-16(2t-3)=14(t+3)+8(3t-1)
21t+7-32t+48=14t+42+24t-8
collect like terms
21t-32t+7+48=14t+24t+42-8
-11t+55=38t+34
-11t-38t=34-55
-49t=-21
-49 -49
t=21
49
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