Solve the following equations: 2x–3y=13 and 7x–2y =20 by elimination method and cross multiple method and verify it by both method.
Pls tell me the correct answer.
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Solve the following equations: 2x–3y=13 and 7x–2y =20 by elimination method and cross multiple method and verify it by both method.
Pls tell me the correct answer.
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2x−3y=13…(1)
7x−2y=20…(2)
Let us use the elimination method for the given system of equations.
Multiply (1) by 2 and (2) by −3. And add both the equations.
4x−21x−+6y6y==26−60−17x=−34x=2
Substitute the value of x in equation (1),
2(2)−3y4−3y−3yy=13=13=9=−3
Hence, the value of x is equal to 2 and that of y is equal to -3
Step-by-step explanation
2x - 3y = 13 .......(1)
7x - 2y = 20 .......(2)
4x - 6y = 26 .........(3)
21x - 6y = 60 .........(4)
subtracting eqn (3) from (4)
17x = 60 - 26 = 34
x = 2
substitute value x = 2 in (1) eqn
4 - 3y = 13
3y = (4 - 13) = -9
y = -3
Hence solution is x = 2 and y = -3